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4.9x^2-12.3x+3.86=0
a = 4.9; b = -12.3; c = +3.86;
Δ = b2-4ac
Δ = -12.32-4·4.9·3.86
Δ = 75.634
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.3)-\sqrt{75.634}}{2*4.9}=\frac{12.3-\sqrt{75.634}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.3)+\sqrt{75.634}}{2*4.9}=\frac{12.3+\sqrt{75.634}}{9.8} $
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